(x+1)^2-6=5x+5

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Solution for (x+1)^2-6=5x+5 equation: 



(x+1)^2-6=5x+5

We move all terms to the left:

(x+1)^2-6-(5x+5)=0

We get rid of parentheses

(x+1)^2-5x-5-6=0

We add all the numbers together, and all the variables

-5x+(x+1)^2-11=0

We move all terms containing x to the left, all other terms to the right

-5x+(x+1)^2=11

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